Mas0n
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CybricsCTF2021复现

CybricsCTF2021复现

好几周前的存稿了….因为懒,所以咕咕咕了…

国外的题目还是很有质量的,考的都是我没遇到过的题

Kernel Reverse

唔,Linux内核逆向…又是一个盲点

ssh连上,发现目录下就一个ioctl.ko

teamx@cyb-driver:~$ file ioctl.ko
ioctl.ko: ELF 64-bit LSB relocatable, x86-64, version 1 (SYSV), BuildID[sha1]=df785cb97d70de2ae5493fa26595d8bd0d1e50a6, with debug_info, not stripped

scp拿出来分析

sub_65发现了疑似flag字段

https://cdn.shi1011.cn/2021/08/27eeb8305faa5c3c7b3c1902916c585c.png?imageMogr2/format/webp/interlace/0/quality/90|watermark/2/text/wqlNYXMwbg/font/bXN5aGJkLnR0Zg/fontsize/14/fill/IzMzMzMzMw/dissolve/80/gravity/southeast/dx/5/dy/5

满足这两个条件即可,且能够在/dev目录下找到ioctl

#include <stdio.h>
#include <string.h>
#include <sys/time.h>
#include <sys/ioctl.h>
#include <fcntl.h>
#include <stdlib.h>


int main() {
    struct timeval t;
    int a2 = 0x5702;

    int fs = open("/dev/ioctl", O_RDWR);
    if (fs == -1)
    {
        printf("open driver error.\n");
        exit(-1);
    }
    printf("open driver success.\n");
    gettimeofday(&t, NULL);
    char flag[128];
    int second = t.tv_sec;
    int a3 = 0x13373389 ^ second;
    memcpy(flag, &a3, 4);
    ioctl(fs, a2, flag);
    printf("%s\n", flag);

    return 0;
}

Listin

SSE……复现,有一些指令没看见过,Google一下

PSHUFB — Packed Shuffle Bytes (felixcloutier.com)

MOVDQA/VMOVDQA32/VMOVDQA64 — Move Aligned Packed Integer Values (felixcloutier.com)

PXOR — Logical Exclusive OR (felixcloutier.com)

分析一遍流程

BITS 64
global check
section .text
check:
    mov rbp, rsp
    sub rsp, 0x100
    VMOVDQA ymm0, [rdi]
    and rsp, 0xffffffffffffff00
    mov rax, 0xfeca50051345b0b0
    push rax
    push rax
    push rax
    push rax
    VMOVDQA ymm1, [rsp]
    VPXOR ymm2, ymm1, ymm0     ; ymm2 = ymm1 ^ ymm0
    mov rax, 0x0100030205040706
    push rax
    mov rax, 0x09080b0a0c0d0f0e
    push rax
    mov rax, 0x1110131215141716
    push rax
    mov rax, 0x19181b1a1c1d1f1e
    push rax
    VMOVDQA ymm3, [rsp]
    VPSHUFB ymm4, ymm2, ymm3    ; ymm2 根据ymm3的内容打乱ymm2中的字节
    mov rax, 0xd1d3762335619aab
    push rax
    mov rax, 0xd5d52327356583f8
    push rax
    mov rax, 0xc9d36127336c85b9
    push rax
    mov rax,0xd5d622713161cbf8 
    push rax
    VMOVDQA ymm0, [rsp]
    VPCMPEQQ  ymm1, ymm4, ymm0  ; ymm4 == ymm0
    VMOVDQA [rsp], ymm1
    pop rax
    cmp rax, 0xffffffffffffffff
    jnz fail
    pop rax
    cmp rax, 0xffffffffffffffff
    jnz fail
    pop rax
    cmp rax, 0xffffffffffffffff
    jnz fail
    pop rax
    cmp rax, 0xffffffffffffffff
    jnz fail
    mov rax, 1
    jmp fin
fail:
    xor rax, rax
fin:
    mov rsp, rbp
    ret

需要注意的是VPSHUFB指令,国内几乎没有具体讲解的文章。于是只能自己看伪代码理解了

https://cdn.shi1011.cn/2021/08/5caa4e99c2fdfedbc692603cf2e42df6.png?imageMogr2/format/webp/interlace/0/quality/90|watermark/2/text/wqlNYXMwbg/font/bXN5aGJkLnR0Zg/fontsize/14/fill/IzMzMzMzMw/dissolve/80/gravity/southeast/dx/5/dy/5

没有详细的注释,仔细看几遍就能大致理解流程了

然后就是根据流程写脚本

import struct


def parseBytes(ymm: list):
    arr = []
    for j in ymm:
        arr.extend(struct.pack("<Q", j))
    return arr


ymm1 = [0xfeca50051345b0b0, 0xfeca50051345b0b0, 0xfeca50051345b0b0, 0xfeca50051345b0b0]  # XorKeys
ymm3 = [0x19181b1a1c1d1f1e, 0x1110131215141716, 0x09080b0a0c0d0f0e, 0x0100030205040706]  # Tables
ymm0 = [0xd5d622713161cbf8, 0xc9d36127336c85b9, 0xd5d52327356583f8, 0xd1d3762335619aab]  # EncData
# https://www.felixcloutier.com/x86/pshufb#fig-4-15
(KL, VL) = (32, 256)
jmask = (KL - 1) & ~0XF

TbArrs = parseBytes(ymm3)

for i in range(len(TbArrs)):
    TbArrs[i] = (TbArrs[i] & 0xF) + (i & jmask)

print("VPSHUFB Tables:", TbArrs)

xorDataArr = [0] * len(TbArrs)
shuffleArr = parseBytes(ymm0)

for i, v in enumerate(TbArrs):
    xorDataArr[v] = shuffleArr[i]


ymm4 = []
xorKey = parseBytes(ymm1)

for i in range(len(xorDataArr)):
    ymm4.append(xorKey[i] ^ xorDataArr[i])

flag = "".join([chr(i) for i in ymm4])
print(flag)
本文链接:https://blog.shi1011.cn/ctf/1544
本文采用 CC BY-NC-SA 3.0 Unported 协议进行许可

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CybricsCTF2021复现
好几周前的存稿了....因为懒,所以咕咕咕了... 国外的题目还是很有质量的,考的都是我没遇到过的题 Kernel Reverse 唔,Linux内核逆向…又是一个盲点 ssh连上,发现目录下就…
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2021-08-20